HCOONa is commonly a sodium salt of formic acid and has the potential đồ sộ react with strong acids. Let us see the mechanism of its reaction with H_{2}SO_{4}.

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**Sodium formate, also known as sodium methanoate, combines with sulfuric acid đồ sộ synthesize formic acid. HCOONa is formed by absorbing carbon monoxide in solid sodium hydroxide. It appears as white deliquescent granules that, when exposed đồ sộ moisture, transform into liquid. H _{2}SO_{4} is a colorless, strong oxidizing agent.**

The following sections of the article shall discuss in detail the reaction between HCOONa and H_{2}SO_{4}, the products formed, enthalpy of the reaction, the reaction type, etc.

**What is the product of H**_{2}SO_{4} and HCOONa?

_{2}SO

_{4}and HCOONa?

**Formic acid and Sodium sulfate are formed as major products when HCOONa is reacted with H _{2}SO_{4}.**

**2HCOONa + H _{2}SO_{4 }—>**

**2HCOOH + Na**

_{2}SO_{4}

**What type of reaction is H**_{2}SO_{4} + HCOONa?

_{2}SO

_{4}+ HCOONa?

**H _{2}SO_{4} + HCOONa is an example of double displacement reaction, also referred đồ sộ as a salt metathesis reaction.**

**How đồ sộ balance H**_{2}SO_{4} + HCOONa

_{2}SO

_{4}+ HCOONa

**The balanced chemical equation for H _{2}SO_{4} + HCOONa reaction is:**

**2HCOONa + H _{2}SO_{4 }= 2HCOOH + Na_{2}SO_{4}**

**Following are the steps đồ sộ equate the reaction mentioned above:**

**The unbalanced equation is first written down, i.e.: HCOONa + H**_{2}SO_{4}= HCOOH + Na_{2}SO_{4}**The number of atoms or elements present on both reactant and product sides are counted and tabulated.**

Atoms | Reactant Side | Product Side |
---|---|---|

Sodium | 1 | 2 |

Sulfur | 1 | 1 |

Carbon | 1 | 1 |

Hydrogen | 3 | 2 |

Oxygen | 6 | 6 |

**Count of atoms on reactant and product side**

**Necessary coefficients are then added đồ sộ the unbalanced atoms đồ sộ establish the balanced reaction.****To balance sodium atoms, HCOONa molecule was multiplied by coefficient 2.****Secondly, hydrogen was equated on both sides by multiplying HCOOH by coefficient 2.****Thus, the balanced chemical equation for the given reaction is as follows:****2HCOONa + H**_{2}**SO**_{4 }**—> 2HCOOH + Na**_{2}SO_{4}

**H**_{2}SO_{4} + HCOONa Titration

_{2}SO

_{4}+ HCOONa Titration

**HCOONa cannot be titrated against H _{2}SO_{4 }as HCOONa is a monosodium salt of a weak acid. Thus, without a base, H_{2}SO_{4} and HCOONa titration would yield no significant results.**

**H**_{2}SO_{4} + HCOONa Net Ionic Equation

_{2}SO

_{4}+ HCOONa Net Ionic Equation

**The net ionic equation between H _{2}SO_{4} and HCOONa is: HCOO^{–} + Na^{+} + 2H^{+} + SO_{4}^{2-} = HCOO^{–} + H^{+} + 2Na^{+} + SO_{4}^{2-}**

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**The following are the steps đồ sộ derive the net ionic equation:**

**Firstly, the complete balanced equation is noted.****2HCOONa + H**_{2}SO_{4}=**2HCOOH + Na**_{2}SO_{4}**The reacting atoms are then dissociated into their respective ions đồ sộ give the net ionic equation; for example, HCOONa splits in an aqueous solution đồ sộ give HCOO**^{–}and Na^{+}ions.**In the next step, spectator ions, if any, are eliminated from both sides of the reaction.****The final net ionic equation for H**_{2}SO_{4}+ HCOONa reaction is mentioned in the next step.**HCOO**^{–}+ Na^{+}+ 2H^{+}+ SO_{4}^{2-}= HCOO^{–}+ H^{+}+ 2Na^{+}+ SO_{4}^{2-}

**H**_{2}SO_{4} + HCOONa Conjugate Pairs

_{2}SO

_{4}+ HCOONa Conjugate Pairs

**The conjugate pairs formed between reaction H _{2}SO_{4} + HCOONa are mentioned below:**

**Conjugate base of H**_{2}SO_{4}(after donating a proton) = HSO_{4}^{–}**Conjugate base of HCOOH = HCOO**^{–}

**H**_{2}SO_{4} and HCOONa Intermolecular Forces

_{2}SO

_{4}and HCOONa Intermolecular Forces

**For H**_{2}SO_{4},**Van der waals dispersion forces****, dipole-dipole interactions, and strong intermolecular hydrogen bonding forces are present as intermolecular forces.****HCOONa exhibit electrostatic attraction, implying that Ionic intermolecular forces exist due đồ sộ the presence of two ionic species, Na**^{+}and HCOO^{–}.

**H**_{2}SO_{4} + HCOONa Reaction Enthalpy

_{2}SO

_{4}+ HCOONa Reaction Enthalpy

**The reaction enthalpy of H _{2}SO_{4} + HCOONa is 5.73 kJ/mol (approximately).**

Compounds | Moles | Enthalpy of Formation, ΔH⁰_{f} (kJ/mol) |
---|---|---|

H_{2}SO_{4} | 1 | -909.27 |

HCOONa | 2 | -666.5 |

HCOOH | 2 | -424.72 |

Na_{2}SO_{4} | 1 | -1387.1 |

**Bond Enthalpy values**

**The standard enthalpy of a reaction is calculated using the formula: ΔH⁰**_{f (reaction)}= ΣΔH⁰_{f (products) }– ΣΔH⁰_{f (reactants)}**Enthalpy of reaction = [2×(-424.72) + 1× (-1387.1)] – [2×(-666.5) + 1×(-909.27)] = 5.73 kJ/mol**

**Is H**_{2}SO_{4} + HCOONa a Buffer Solution?

_{2}SO

_{4}+ HCOONa a Buffer Solution?

**H**_{2}SO_{4}+ HCOONa is not a buffer solution because H_{2}SO_{4}is a strong acid, and no conjugate acid or base is present đồ sộ resist the pH change.**However, HCOOH produced in this reaction may combine with HCOONa đồ sộ give an acidic buffer.**

**Is H**_{2}SO_{4} + HCOONa a Complete Reaction?

_{2}SO

_{4}+ HCOONa a Complete Reaction?

**H**_{2}SO_{4}+ HCOONa is a complete reaction as it forms two complete products, HCOOH and Na_{2}SO_{4}.**However, at temperatures ranging from 25 đồ sộ 170⁰C, HCOOH may further decompose đồ sộ produce carbon monoxide gas and water.**

**Is H**_{2}SO_{4 }and HCOONa an Exothermic or Endothermic Reaction?

_{2}SO

_{4 }and HCOONa an Exothermic or Endothermic Reaction?

**The given reaction is endothermic since the change in enthalpy is positive. As a result, external energy is absorbed by the reaction đồ sộ reach completion.**

**Is H**_{2}SO_{4} + HCOONa a Redox Reaction?

_{2}SO

_{4}+ HCOONa a Redox Reaction?

**H _{2}SO_{4} + HCOONa is not a redox reaction since no change in the oxidation states of elements is observed on both sides of the reaction.**

**Is H**_{2}SO_{4} + HCOONa a Precipitation Reaction?

_{2}SO

_{4}+ HCOONa a Precipitation Reaction?

**H _{2}SO_{4} + HCOONa is not a precipitation reaction because both the products obtained are highly soluble in water,**

**ruling out the possibility of precipitate formation.**

**Is H**_{2}SO_{4 }+ HCOOH Reversible or Irreversible Reaction?

_{2}SO

_{4 }+ HCOOH Reversible or Irreversible Reaction?

**H _{2}SO_{4} + HCOONa is irreversible in nature because the products formed can no longer perform reverse reactions đồ sộ synthesize the reactants under the same reaction conditions.**

**Is H**_{2}SO_{4 }+ HCOOH Displacement Reaction?

_{2}SO

_{4 }+ HCOOH Displacement Reaction?

**H _{2}SO_{4} + HCOONa is a double displacement reaction because of the cationic and anionic exchange of atoms that occurs during product formation.**

**Conclusion**

H_{2}SO_{4} and HCOONa reaction is one of the ways đồ sộ synthesize formic acid, an important intermediate, and sodium sulfate, which is employed as an efficient drying agent in organic reactions. Formic acid mainly has varied uses in the field of agriculture as a preservative, in fuel cell, as a pH modifier, and ví on.

Read more facts on H2SO4:

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